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CBSE Class 10 Sample Paper for 2019 Boards

Paper Summary

Question 1

Question 2 (Or 1st)

Question 2 (Or 2nd) Important

Question 3 (Or 1st) Important

Question 3 (Or 2nd)

Question 4

Question 5 Important

Question 6 Important

Question 7 (Or 1st)

Question 7 (Or 2nd) Important

Question 8 (Or 1st)

Question 8 (Or 2nd)

Question 9

Question 10 Important

Question 11 Important

Question 12 Important

Question 13 Important

Question 14

Question 15

Question 16 (Or 1st) Important

Question 16 (Or 2nd)

Question 17 (Or 1st) Important You are here

Question 17 (Or 2nd)

Question 18 Important

Question 19 (Or 1st)

Question 19 (Or 2nd) Important

Question 20

Question 21 (Or 1st) Important

Question 21 (Or 2nd)

Question 22

Question 23 (Or 1st) Important

Question 23 (Or 2nd)

Question 24

Question 25

Question 26

Question 27 (Or 1st)

Question 27 (Or 2nd) Important

Question 28 (Or 1st)

Question 28 (Or 2nd) Important

Question 29

Question 30 Important

CBSE Class 10 Sample Paper for 2018 Boards →
Class 10
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  • CBSE Class 10 Sample Paper for 2019 Boards

  • CBSE Class 10 Sample Paper for 2018 Boards

Question 17 (OR 1 st question)

Prove that cot ⁡θ - tan ⁡θ = (2 cos 2 ⁡θ  - 1) / (sin⁡ θ cos ⁡θ)

Prove that cot ⁡θ - tan ⁡θ = (2 cos^2 ⁡θ - 1) / (sin⁡ θ cos ⁡θ)

Question 17 (Or 1st) - CBSE Class 10 Sample Paper for 2019 Boards - Part 2


Transcript

Question 17 (OR 1st question) Prove that cot⁡𝜃−tan⁡𝜃 = (2 cos^2⁡𝜃 − 1)/(sin⁡𝜃 cos⁡𝜃 ) Solving LHS cot⁡𝜃−tan⁡𝜃 = cos⁡𝜃/sin⁡𝜃 −sin⁡𝜃/cos⁡𝜃 = (cos⁡𝜃 × cos⁡𝜃 − sin⁡𝜃 × sin⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) = (cos^2⁡𝜃 − sin^2⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) Now, sin2 θ + cos2 θ = 1 sin2 θ = 1 – cos2 θ = (cos^2⁡𝜃 − (1 − cos^2⁡𝜃))/(sin⁡𝜃 cos⁡𝜃 ) = (cos^2⁡𝜃 − 1 + cos^2⁡𝜃)/(sin⁡𝜃 cos⁡𝜃 ) = (2 cos^2⁡𝜃 − 1)/(sin⁡𝜃 cos⁡𝜃 ) = RHS Since LHS = RHS Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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